2007-10-12 13:52:23 · 14 answers · asked by Anonymous in Sports ➔ Baseball
SO far, proud to be mexican in closest, everybody wrong!
2007-10-12 13:57:48 · update #1
Ok, two people got it... first to get it was.........
2007-10-12 14:02:16 · update #2
lee.timmy!
2007-10-12 14:02:44 · update #3
well actually. more than 27
because what if one swings and misses in the dirt
and hes safe on first.
that's still technically a strikeout. But it's not an OUT on the record.
so more than 27.
2007-10-12 13:58:14 · answer #1 · answered by Anonymous · 2⤊ 0⤋
The number is unlimited. Here's my reasoning:
In the first inning, the pitcher strikes out the first two batters. The third batter also strikes out, but the ball gets away from the catcher. The runner makes it to first ahead of the throw and is safe. The inning continues with two outs even though the pitcher now has three strikeouts. This can happen two more times to load the bases. Then one or more batters reach safely and runs score, and as long as one or more bases are free, the dropped third strike can happen again and again. Theoretically, an inning could go on forever. It'll never happen, but it's theoretically possible.
The previous answers of going on forever solely due to dropped third strikes or passed balls is incorrect. If the bases are loaded when a third strike is dropped or not caught, the catcher needs only to touch home in possession of the ball or toss to someone covering home, to force the runner coming from third. The rules of baseball state that once a batter becomes a runner, with the bases loaded, a forceout can be made. This is true even if the batter becomes a runner after striking out.
2007-10-12 14:10:47 · answer #2 · answered by curtisports2 7 · 3⤊ 0⤋
Nope, it particularly is by no potential passed off before. The checklist for strikeouts in a 9-inning interest is 20, performed by utilising Roger Clemens two times, Kerry wood and Randy Johnson. Tom Cheney struck out 21 batters even though it replaced into in a sixteen-inning interest.
2016-11-08 03:40:39 · answer #3 · answered by ? 4 · 0⤊ 0⤋
It would have to be 54 for the following reason: 3 outs per inning for 9 innings = 27, but you could actually have the catcher drop the ball on strike three on three other batters in each inning (without the other team scoring). Therefore 27 + 27 = 54.
2007-10-13 02:26:15 · answer #4 · answered by P.I. Stingray 6 · 0⤊ 2⤋
If you have a lousy catcher and first base is open with less than 2 out, or he's lousy with 2 outs, or both, it's endless due to the dropped-strike-three rule. Of course, if the manager doesn't yank him OR you after a while he needs to go, thus you'll never see 9 innings!
So, put that in your lee.timmy LOL
2007-10-12 17:37:00 · answer #5 · answered by pricehillsaint 5 · 0⤊ 1⤋
27 because there is 27 outs in a game, Unless when they Strike out the Guy and the Ball gets Away then that's a different story
2007-10-12 13:56:04 · answer #6 · answered by Janet ♥(YFFL) 7 · 1⤊ 2⤋
There's no limit, because if the ball keeps getting away every time the pitcher could strike people out forever, theoretically.
2007-10-12 14:00:10 · answer #7 · answered by ousooners4life 3 · 2⤊ 1⤋
27! well in theory, anyways. i bet it'll be a while before that ever happens though!!! 3 strikeouts in an inning itself is rare, imagine 27 straight strikeouts!!!
would you be excited to see history or bored because nobody hit the ball?
2007-10-12 13:56:46 · answer #8 · answered by Purple People Eater 4 · 0⤊ 3⤋
27 strikeouts
2007-10-12 13:56:11 · answer #9 · answered by Beth 3 · 0⤊ 3⤋
Infinite. Techically he can strike someout and do to a passed ball they get on pass. Theorectically this can go on forever.
2007-10-12 14:09:04 · answer #10 · answered by MyNameAShadi 5 · 1⤊ 0⤋