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7 (4 - (23/17)^x ) is greater than or equal to 6

2007-10-12 12:56:01 · 2 answers · asked by jigsawtaz 1 in Science & Mathematics Mathematics

If possible, can you put the answer in interval notation?

2007-10-12 13:10:38 · update #1

2 answers

(4 - (23/17)^x ) ≥ 6/7
4- 6/7 ≥ (23/17)^x
22/7 ≥ (23/17)^x
ln(22/7) ≥ xln(23/17)
x ≤ ln(22/7)/ln(23/17)

2007-10-12 13:02:21 · answer #1 · answered by sahsjing 7 · 0 0

7 (4 - (23/17)^x ) >= 6 I assume 7 is part of problem.
(4 - (23/17)^x ) >= 6/7
-(23/17)^x >= 6/7 -4 = -22/7
(23/17)^x <= 22/7
ln(23/17)^x <= ln(22/7)
x ln(23/17) <= ln(22/7)
x <= ln(22/7)/ln(23/17)

2007-10-12 20:13:15 · answer #2 · answered by ironduke8159 7 · 0 0

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