a point on the terminal side of angle of 60 degrees is given. find the exact value of the indicated?

Question

trigonometric function of 60 degrees. (21,28) find sin 60 degrees.

1. 3/5
2. 3/4
3. 4/5
4. 4/3

Answer 1

3. 4/5

Answer 2

Your question makes no sense. The sine of 60 degrees
= .5sqrt(3) approx = .866
The point (21,28) does not lie on the terminal side of a 60 degree angle. The point 21,28 lies on the terminal side of an angle = arctan(4/3) approx = 53.13 degrees.

Answer 3

shall we see if u r surprising. the scale of the terminal area is sqrt (15^2 + 20^2) = 25. so x = 15 , y = 20 , terminal length r = 25 cos theta = 15/25 = 3/5 u r surprising.sturdy job!