the ferris wheel at the 1893 world's Columbian exposition i Chicago had a diameter of 250ft. Its 36 passenger cabs could hold a total of 2160 people. Suppose the cabs were evenly spaced. About how far apart would they have been?
I need help and i need someone to show me the steps in words and numbers. THANK YOU VERY MUCH
2007-10-12 12:00:20 · 7 answers · asked by N3N4 1 in Science & Mathematics ➔ Mathematics
The diameter is 250ft.
The circumference (distance around the perimeter of the circle) would be:
pi * diameter
= pi * 250 ft
= 785.4 ft
The space between each car would then be found by dividing the circumference by 36:
= 785.4/36
=21.8 ft
2007-10-12 12:05:11 · answer #1 · answered by Quocamus 2 · 1⤊ 0⤋
The circumference of the wheel = ÏD
Where Ï = 3.14
and D = Diameter = 250 ft
circumference = 3.14 x 250 ft
= 785 ft
Spacing of cabs = 785 / 36 ft
= 21.805555 ft
= 21 ft 9.66 inches
2007-10-12 12:15:10 · answer #2 · answered by Anonymous · 0⤊ 0⤋
Perimeter of Circle = pi * Diameter
= pi * 250 ft
No. of cabs = 36
Therefore space between them = pi * 250 / 36=21.8 ft
2007-10-12 12:06:47 · answer #3 · answered by ib 4 · 0⤊ 0⤋
find the circumference which is Pi times d. pi is 3.14 and d is given as 250. divide the circ by 36 and this answer is how far apart the cars are
2007-10-12 12:12:31 · answer #4 · answered by Anonymous · 0⤊ 0⤋
I think:
The circumference of a circle can be calculated from its diameter using the formula: Pie (3.141) times diameter
so if your diameter is 250 ft. then multiply it by 3.141 which equals 785.25 feet.
785.25 feet divided by 36 = 21.8125 feet apart
2007-10-12 12:14:18 · answer #5 · answered by MICHAEL Z 3 · 0⤊ 0⤋
circumference of wheel=2*3.14*diam/2
spacing = circumference/36
# op passenger don't matter
2007-10-12 12:06:00 · answer #6 · answered by ry0534 6 · 0⤊ 0⤋
250 * cos 85° â 21.8 feet
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2007-10-12 12:13:15 · answer #7 · answered by oregfiu 7 · 0⤊ 0⤋