Initially this problem seems to be in simplist form but I think I am missing the method for tackling the square root of 8.
2007-10-12 11:33:50 · 5 answers · asked by Troubled with Numbers 1 in Science & Mathematics ➔ Mathematics
a(square root 8) - 3(square root 2a^2)
= a * 8^(1/2) - 3a(2^1/2)
= a * 2^(3/2) - 3a(2^1/2)
= 2a*2(^1/2) - 3a(2^1/2)
= -a*2(^1/2)
= -a * sqrt(2)
2007-10-12 11:40:37 · answer #1 · answered by ib 4 · 0⤊ 0⤋
a√8 -3√(2a^2)
= a√(2*2*2) - 3√(2*a*a)
... when you have two of the same thing in a sqrt you can it out as a 'factor... we have three 2s so we take two out and but a two in front of the √ symbol... this is like saying a√4 = a√(2*2) = 2a
= 2a√2 -3a√2
= -a√2
2007-10-12 11:41:14 · answer #2 · answered by David F 5 · 0⤊ 0⤋
-a square root of 2
2007-10-12 11:41:44 · answer #3 · answered by john 4 · 0⤊ 1⤋
= 2asqrt(2) - 3asqrt(2) = -asqrt(2)
2007-10-12 11:39:21 · answer #4 · answered by ironduke8159 7 · 0⤊ 0⤋
a{sq rt(8)}-3{sq rt(2a^2)}
=a{sq rt(2*2^2)}-3{sq rt(2)}a
=2a{sq rt(2)}-3a{sq rt(2)}
=sq rt(2)(2a-3a)
=-a sq rt(2) ans
2007-10-12 13:25:17 · answer #5 · answered by MAHAANIM07 4 · 0⤊ 0⤋