Its very simple yaar.
First of all see ur equation:
4x/(3x+7)=3/4.
In every sum like this u should cross multiply and get the answer:
4(4x)=3(3x+7)
Now *&÷ for getting the answer:
16x=9x + 21
7x=21
x=3.
In every sum to find x(a,b....z) u should follow the same method but u should knoe the factors.
Try this:
7x/3=(9x-7)/5.
2007-10-12 14:43:09
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answer #1
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answered by Aariz 2
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I think the question is not written correctly.
since,
4x/3x+7=4/3+7=25/3 which is not equal to 3/4.
positioning of bracket is important!
If you mean the question is 4x/(3x+7)=3/4 then it had already been answered by others.
2007-10-15 04:56:30
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answer #2
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answered by Roy 2
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Multiply by 3x+7 to get
4x=3(3x+7)/4
Multiply both sides by 4
16x=3(3x+7)
Distribute
16x=9x+21
Subtract 9x
7x=21
Divide by 7
x=3
2007-10-12 10:36:58
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answer #3
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answered by Anonymous
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Multiply by 3x+7 to get
4x=3(3x+7)/4
Multiply both sides by 4
16x=3(3x+7)
Distribute
16x=9x+21
Subtract 9x
7x=21
Divide by 7
x=3
2007-10-12 10:33:40
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answer #4
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answered by Smrt 1
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4x/(3x+7)=3/4
Cross multiply getting:
3(3x+7) = 4*4x
9x+21 =16x
21 = 7x
x = 3
2007-10-12 10:34:13
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answer #5
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answered by ironduke8159 7
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4x/3x+7=3/4
=4x(4)=3(3x+7) [when u cross multiply]
16x=9x+21
16x-9x=21
7x=21
x=21/7=3
x=3
2007-10-12 22:45:58
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answer #6
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answered by Anonymous
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is that 4x / (3x+7) = 3/4 <-- Call this A
or 4x/3x+7 = 3/4 <-- Call this B
A,
4x / (3x+7) = 3/4
4x = (3/4) *(3x+7)
16x = 3(3x+7) = 9x +21
21 = 7x
x = 3
B
4x/3x+7 = 3/4
x = (3/4 - 7) * 3/4)
x = -6.25 * 0.75 = -4.6875 or 4 11/16 (four and 11 sixteenths
2007-10-12 10:32:40
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answer #7
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answered by David F 5
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The way you wrote it the x's cancel out and just leaves numbers. Next time use parenthesis around the 3x+7 term.
2007-10-12 11:09:08
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answer #8
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answered by andyg77 7
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4x/(3x+7)=3/4
or 4x*4=3*(3x+7)
or 16x=9x+21
or 16x-9x=21
or 7x=21
or x=3 ans
2007-10-13 09:35:34
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answer #9
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answered by MAHAANIM07 4
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its too easy . transpose4 to 4x and 3x+7 to 3 you will get 21x=9x+7
> then,
16x-7=9x
> -7=9x-21x
> -7= -12x
negative sign will get cancel
> x=7/12
2007-10-13 06:11:23
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answer #10
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answered by manas n 1
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