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2 answers

F(t) = ∫3/t^2 = -3/t

F'(x) = d/dx∫ 3/t^2 from 1 to x



=> d/dx[F(x) - F(1) ]= d/dx[-3/x +d/dx (3)]


= 3/x^2

2007-10-12 10:36:34 · answer #1 · answered by mohanrao d 7 · 0 0

3/x^2.

2007-10-12 10:31:51 · answer #2 · answered by Tony 7 · 0 0

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