x-y+z = 0
2x+y+3z=0
2007-10-12 09:47:13 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
x-y+z = 0
2x+y+3z=0
3x + 4z = 0
3x = - 4z
Ratio of x to z is 3:-4
2007-10-12 09:50:55 · answer #1 · answered by Axis Flip 3 · 0⤊ 0⤋
x-y+z = 0
2x+y+3z=0
Add the above two linear equations getting:
3x +4z = 0
3x = -4z
x/z = -4/3
2007-10-12 10:03:05 · answer #2 · answered by ironduke8159 7 · 0⤊ 0⤋
given: x-y+z=0 and 2x+y+3z+0 find ratio of x to z:
solving for y: y-x-z=0 or y=x+z
substituting for y in the second equation:
2x+(x+z)+3z=0 or 3x+4z=0 and 3x=-4z and finally:
the ratio of x to z is 3 to 4.
2007-10-12 10:09:43 · answer #3 · answered by Franklin G 1 · 0⤊ 0⤋
x-y+z = 0
2x+y+3z=0
y =x+z
2x+x+z +3z =0
3x+4z =0
3x =-4z
x/z = -4/3
2007-10-12 09:52:53 · answer #4 · answered by Any day 6 · 1⤊ 1⤋
solve for y in each and set them equal:
y=x+z & y=-2x-3z so x+z=-2x-3z
so 3x=-4z.
to get ratio of x to z is the same as x/z so the equation becomes:
x/z=-(4/3)
2007-10-12 09:52:41 · answer #5 · answered by Damian M 3 · 0⤊ 1⤋