find dy/dx for the parametric equations x = 2 sin t, y = 2 cos t?

0 ⤊

find dy/dx for the parametric equations x = 2 sin t, y = 2 cos t

2007-10-12 09:10:15 · 4 answers · asked by brownk_1999 1 in Science & Mathematics ➔ Mathematics

dx = 2cost(dt) dy = -2sint(dt)

dy/dx = -sint/cost = -tan(t)

2007-10-12 09:17:36 · answer #1 · answered by supastremph 6 · 0⤊ 0⤋

x = 2sint
dx/dt = 2cost

y = 2cost
dy/dt = -2sint

dy/dx = (dy/dt) / (dx/dt) = -2sint / 2cost = -tant

2007-10-12 16:17:52 · answer #2 · answered by Anonymous · 0⤊ 0⤋

x = 2 sin t
dx = 2cos t dt

y = 2cos t
dy = -2sin t dt

dy/dx = (-2sin t dt )/(2cos t dt)
or dy/dx = -tan t

2007-10-12 16:18:42 · answer #3 · answered by ib 4 · 0⤊ 0⤋

x = 2cost
y = -2sint

2007-10-12 16:17:47 · answer #4 · answered by Here's Johnny! 3 · 0⤊ 0⤋