find y' of y= 2x sin x - x^2 tan x?

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find y' of y= 2x sin x - x^2 tan x

2007-10-12 08:25:28 · 4 answers · asked by jewel7962002 1 in Science & Mathematics ➔ Mathematics

y' = 2sinx + 2x(cosx) - 2x(tanx) - (x^2)(sec^2(x))

2007-10-12 08:31:56 · answer #1 · answered by Anonymous · 0⤊ 0⤋

y' = 2x cos x + 2sin x - x^2 sec^2 x - 2x tan x
y' = 2 sin x + 2x (cos x - tan x) - x^2 sec^2 x

2007-10-12 15:32:18 · answer #2 · answered by landonastar 3 · 0⤊ 0⤋

y= 2x sin x - x^2 tan x
y' = 2xcos x +2sinx -x^2sec^2 x -2xtan x

2007-10-12 15:34:22 · answer #3 · answered by ironduke8159 7 · 0⤊ 0⤋

dy/dx = 2sin(x) +2x cos(x) - 2x tan(x) - x^2 sec^2(x)

2007-10-12 15:33:14 · answer #4 · answered by nyphdinmd 7 · 0⤊ 0⤋