and solve 40=(sqrt of x)/x
2007-10-12 07:02:27 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
40 = SQRT(x)/x
now square both sides to get rid of the root
1600 = x/x^2
1600 = 1/x
1600x = 1
x = 1/1600
x = 0.000625
2007-10-12 07:05:13 · answer #1 · answered by TheOtterRules 2 · 0⤊ 0⤋
40=(sqrt of x)/x
=> 40 = 1 / âx
=> âx = 1 / 40
=> x = 1 / 1600
2007-10-12 07:11:12 · answer #2 · answered by Madhukar 7 · 0⤊ 0⤋
as x must be >0
sqrt(x) / x= sqrt(1/x) so 1/x= 1600 and x = 1/1600
2007-10-12 07:10:01 · answer #3 · answered by santmann2002 7 · 0⤊ 0⤋
First try to simplyfy the equation.Dnt keep a denominator
so 1/x=x^-1 so Sqx/x=x^-1/2 = 1/sqX
then
40=1/sqx
sqx=1/40
x = 1/sq40
x=1/sq(10 x 4)
x=1/2sq10
2007-10-12 08:12:19 · answer #4 · answered by Anonymous · 0⤊ 0⤋
sqrt(x)/x=1/sqrt(x)=x^(-0.5)
when40=1/sqrt(x)
1600=1/x
then x=1/1600
2007-10-12 07:07:31 · answer #5 · answered by rajini 2 · 0⤊ 0⤋