Calculate the percent ionization of nitrous acid in a solution that is 0.249 M in nitrous acid. The acid disso

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Calculate the percent ionization of nitrous acid in a solution that is 0.249 M in nitrous acid. The acid disso

Calculate the percent ionization of nitrous acid in a solution that is 0.249 M in nitrous acid. The acid dissociation constant of nitrous acid is 4.5x 10to the negative 4?

2007-10-12 05:44:00 · 2 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry

2 answers

HNO2 <----> H+ + NO2-
initial concentration
0.249
at equlibrium
0.249-x . . .. . x .. . . . x
4.5 x 10^-4 = x^2 / 0.249-x
x = 0.0106 M
0.249 - 0.0106 = 0.238 M
0.238 x 100 / 0.249 = 95.7%

2007-10-12 07:57:30 · answer #1 · answered by Dr.A 7 · 0⤊ 2⤋

Work out root (Ka / 0.249) and then multiply by 100.

2007-10-12 06:07:04 · answer #2 · answered by Gervald F 7 · 1⤊ 0⤋