2007-10-12 05:28:18 · 10 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
36x²-16=0
4(9x² -4) = 0
4(3x - 2)(3x+2) = 0
2007-10-12 05:33:25 · answer #1 · answered by MamaMia © 7 · 1⤊ 0⤋
36x^2 - 16 = 0
(6x + 4)(6x - 4) = 0
6x + 4 = 0, 6x = - 4, x = - 2/3
6x - 4 = 0, 6x = 4, x = 2/3
Answer: x = 2/3 or - 2/3
Proof where x = 2/3:
36(2/3^2) - 16 = 0
36(4/9) - 16 = 0
16 - 16 = 0
Proof where x = - 2/3:
36(- 2/3^2) - 16 = 0
36(4/9) - 16 = 0
16 - 16 = 0
2007-10-12 06:40:22 · answer #2 · answered by Jun Agruda 7 · 2⤊ 0⤋
36x²-16=0
=> (6x - 4)(6x + 4)= 0
=> 6x + 4 = 0, 6x = - 4, x = - 2/3
=> 6x - 4 = 0, 6x = 4, x = 2/3
2007-10-12 05:32:52 · answer #3 · answered by harry m 6 · 0⤊ 0⤋
the optimal undemanding section of 36x and 6x^2 is 6x. because of the fact 6 is the optimal undemanding section of 6 and 36 (6 * 6 = 36), and x the optimal section of x and x^2 (x * x = x^2) So, 36x + 6x^2 = (6x * 6) + (6x * x) = 6x(6+x)
2016-12-29 06:23:25 · answer #4 · answered by Anonymous · 0⤊ 0⤋
36 x ² = 16
x ² = 16 / 36 = 4 / 9
x = ± 2 / 3
2007-10-13 21:23:07 · answer #5 · answered by Como 7 · 0⤊ 0⤋
first you reduce the equation by factoring out a 4 since both numbers are divisible by 4
You get:
4(9x^2-4)
(9x^2-4) is a difference of squares problem. The square root of 9x^2 is 3x and the square root of 4 is 2. One of the factors will be the difference of the square roots and the other will be the addition of the square roots
Hence:
(3x+2)(3x-2)
Don't forget the 4 that was factored out earlier
The answer is 4(3x+2)(3x-2)
2007-10-12 05:51:04 · answer #6 · answered by Anonymous · 0⤊ 0⤋
36x² - 16 = 0
(6x - 4)(6x + 4) = 0
- - - - - - - -s-
2007-10-12 05:34:36 · answer #7 · answered by SAMUEL D 7 · 0⤊ 0⤋
This is in the form a^2 - b^2, which we know by formula is (a+b)(a-b).Here, (6x)^2 - (4)^2 = (6x+4)(6x-4) = 0. O.K.?
2007-10-12 05:38:27 · answer #8 · answered by Pandian p.c. 3 · 0⤊ 0⤋
(6x +4)(6x - 4)
2007-10-12 05:38:15 · answer #9 · answered by Anonymous · 0⤊ 0⤋
mamamia's answer is right.
2007-10-12 05:50:19 · answer #10 · answered by chemistrychicka 1 · 0⤊ 0⤋