2007-10-12 05:24:05 · 6 answers · asked by suzukiracer6789 1 in Science & Mathematics ➔ Mathematics
2 solutions
[16+t]=2t-3
=> 16+t = ±(2t-3)
2007-10-12 05:28:09 · answer #1 · answered by harry m 6 · 1⤊ 0⤋
if the question is written wisely the place in common terms the left side has rather the value, then there is strictly one million answer to the question (t=19). If rather the value had blanketed the whole equation then there could be 2 solutions additionally, the consumer that reported that -13/3 grow to be an answer, it rather is incorrect. It yields 11.sixty seven = -11.sixty seven, which isn't incredible
2016-12-14 15:37:25 · answer #2 · answered by ? 4 · 0⤊ 0⤋
16+t=2t-3
or
16+t=-(2t-3)
one for each ,
then 2 all together
2007-10-12 05:31:14 · answer #3 · answered by Miao Yong 2 · 1⤊ 0⤋
There are two solutions. t= -2/7 and t = 1/9.
2007-10-12 05:30:57 · answer #4 · answered by ironduke8159 7 · 0⤊ 1⤋
case 1: 16+t > 0
|16+t| = 16+t
and solve
case 2: 16+t < 0
|16+t| = -(16+t) = -16-t is your left hand side.
solve.
2007-10-12 05:32:13 · answer #5 · answered by cidyah 7 · 1⤊ 0⤋
one
2007-10-12 05:27:21 · answer #6 · answered by ib 4 · 1⤊ 1⤋