How to find the inverse of of this function: y + 7 = x^3?

Question

all i know is tht:
1) set equation to y---so y= x^3 - 7
2) switch x and y---- so x = y^3 - 7
3) solve for y
4) put in inverse notation

i do not know how to do number 3 or 4....for number 3, i need 4....thanks guyz for the help....i understand all the other ones....just this one i am confused on because of the y^3...

Answer 1

ok so you have x +7 = y^3
adn then its as easy as taking the cube root

y= cuberoot(x + 7)
or
y = (x+7)^(1/3)

Answer 2

a million) 6 + 6 ln x = 11 6lnx=5 lnx=fifty six ---> x=e^(5/6) 2) don't understand... 4) -4 ? -4x - 12 < 4 -4 + 12 ? -4x < 4 +12 8 ? -4x < 16 -2 >= x > -4 5) y = (x-7)^3 first you replace y by using x: x = (y-7)^3 then you actually be certain for y y-7 = x^(a million/3) y = x^(a million/3) + 7

Answer 3

y=x^3-7 (this is right)
x^3=y+7
x= (y+7)^(1/3)
is the inverse.
You solve for x, in terms of y.

Answer 4

x = y^3 - 7
x + 7 = y^3
y = (x+7)^(1/3) {cubicroot}

Answer 5

first you solve for x then you switch y
x= cube root of y-7
then switch
y=cube root of x-7