Make t the subject of these two equations?

Question

1) v = u + at.

2) S = ut + 1/2 a t^2.

I could re-write the second as
S = ut + 1/2 a t squared.
I can't write t squared as I can't get the little 2 above the t. Anyone know how to?

Yes, I'm sure it's right....
Granted it's much more difficult than the first. 10 points to the first correct solution

Nick J is correct...you have restored my faith in the British education system...(you ARE British, aren't you?)

Answer 1

1) v = u+at
at = v-u
t = (v-u)/a

2) S = ut + 1/2 a t^2

this is a quadratic, so first re-arrange to the form
0 = ax^2 + bx + c

which gives:
0 = 1/2 at^2 + ut -S

Using the standard quadratic formula:

t = (-u + sqrt(u^2 - 2as)) / a
t = (-u - sqrt(u^2 - 2as)) / a

Yes, there really are 2 answers, that's because a square root of a positive number always has 2 answers.

Answer 2

Question 1
at = v - u
t = (1/a) (v - u)

Question 2
t² s = ut³ + (1/2) a
ut³ - st² + (1/2)a = 0

Answer 3

1) v = u + at.
v - u = at
(v - u) / a = t

Edit
_____________

2) S = ut + 1/2 a t^2.

if as Nick said below, you do it as a quadratic

1/2at^2 + ut - S = 0

it would be
t = (-u + sqrt(u^2 + 2as)) / a
t = (-u - sqrt(u^2 + 2as)) / a

coz the last bit is -4ac
so -4*1/2a*-s
=+2as not -2as

Answer 4

1) t = v-u / a (t equals v minus u divided by a).

Not familiar with the symbol between t and 2 in the second equation so can't help you there.

Answer 5

1. v = u + at
v - u =at

(v - u)/a = t

2. Cannot be done because it is a quadratic formula!