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Solve for x and express the roots in simplest a+bi form.

4 + (5/x^2) = (6/x)

2007-10-12 00:05:26 · 3 answers · asked by journey 1 in Science & Mathematics Mathematics

3 answers

Rearrangingtthis equation we get a quadratic..

4x^2 - 6x = 5 = 0

Using the formula we get x= (6+/-SQRT{36-80)}/8

this reduces to x = 3/4 + (3.3/4)i or x = 3/4 - (3.3/4)i to 2 figures

2007-10-12 00:17:51 · answer #1 · answered by Anonymous · 0 0

to simplify, multiply the acceptable and the backside by using the conjugate of the backside (3 - 5i), then simplify the denominator will become: (3 + 5i)(3 - 5i) = 9 - 25i^2 = 9 + 25 = 34 the numerator will become: (4 + 3i)(3 - 5i) = 12 - 15i^2 - 20i + 9i = 27 - 11i in prevalent form: (27 - 11i) / 34 = 27 / 34 - 11i / 34

2016-12-18 05:27:47 · answer #2 · answered by lacuesta 4 · 0 0

4x² + 5 = 6x
4x² - 6x + 5 = 0
x = [ 6 ± √(36-80) ] / 8
x = [6 ± √(- 44) ] / 8
x = [ 6 ± 2 i √(11) ] / 8
x = 3/4 ± i √11/4

2007-10-12 06:28:31 · answer #3 · answered by Como 7 · 0 0

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