2007-10-09 23:38:50 · 9 answers · asked by chittaranjan r 1 in Science & Mathematics ➔ Mathematics
2^x = 4 x
2^x = 2^2 x
2^x ÷ 2^2 = x
2^(x – 2) = x
Putting values of x to satisfy the equation
x = 4 satisfy the equation.
2007-10-10 00:08:29 · answer #1 · answered by Pranil 7 · 0⤊ 0⤋
What number can we plug in for x?
If x = 4, then 2^4 = 16.
Then, on the right side of the equation, 4(4) = 16.
We get the same answer on both sides of the equation when x = 4.
Then, x = 4.
2007-10-10 06:51:37 · answer #2 · answered by Anonymous · 1⤊ 1⤋
x 2^x = 4x
2^x = 4x/x=4
2^x = 4 = 2^2
Hence,
x = 2
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2007-10-10 07:03:55 · answer #3 · answered by Joymash 6 · 0⤊ 1⤋
x2^x=4x
2^x=4
x=2.
2007-10-10 06:50:56 · answer #4 · answered by amdon 1 · 1⤊ 1⤋
x 2^x = 4x
Dividing by x
2^x = 4
That means x = 2 (2^2 = 4)
2007-10-10 07:08:19 · answer #5 · answered by Swamy 7 · 0⤊ 1⤋
x= 4
2^4 = 16
and
4*4 = 16 (Hence solved)
2007-10-10 06:43:53 · answer #6 · answered by Doctor Q 6 · 1⤊ 1⤋
My friend it's true for some cases like; x=4.
Let's assume; x=5
2^x=2^5=32
4x=4(5)=20
LHS is not equals to RHS.
2007-10-10 07:02:23 · answer #7 · answered by Jimmy 2 · 0⤊ 2⤋
Ok, let's see,
the equation is of the form 2^x = 4x
assuming x is diefferent than zero, we will take the log on both sides of the equation,
log(2^x) = log(4x)
x log(2) = log(4) + log(x)
divide by log(2),
x = log(4)/log(2) + log(x)/log(2)
x-log(x)/log(2)= log(2)
you can continue to simplify from here...
Good luck.
2007-10-10 06:47:01 · answer #8 · answered by alrivera_1 4 · 0⤊ 3⤋
2^x - 4x = 0
x = 4 . . . and . . . x = 0.3099
2007-10-10 07:20:37 · answer #9 · answered by CPUcate 6 · 1⤊ 1⤋