What is the period of k(t) = cos(2t/3)? I found the amplitude and phase shift but am not sure how to find the period for this problem.
Also, if 8 is the amplitude, and 2 is the period, and 0 is the phase shift, what is the rule of the periodic function?
Thanks for explaining!
2007-10-09 19:56:54 · 2 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
Sorry I phrased the above badly. The second part is a separate question, not an extension of the first question.
2007-10-09 20:06:33 · update #1
Ahh sorry I wrote first question wrong (sorry I'm really struggling with this) it's supposed to be cos(2PIt/3)
2007-10-09 20:08:29 · update #2
OK I got the first part, the PIs cancelled. Anyone want to have a go at the second part?
2007-10-09 20:17:21 · update #3
In the equation k(t) = cos(k*t), k is the angular frequency. The angular frequency is 2π*f, where f is the temporal frequency. So the temporal frequency f is k/2π. The period is the reciprocal of the temporal frequency, 1/f, which is 2π/k. In your problem k = 2/3, so the period is
2π*(3/2) = 3•π
2007-10-09 20:03:45 · answer #1 · answered by gp4rts 7 · 0⤊ 0⤋
period of cos(kt) is (2*pi) / k
therefore period of cos(2t/3) is (2*pi) /(2/3) = 3pi
2007-10-10 03:05:34 · answer #2 · answered by qwert 5 · 0⤊ 0⤋