2007-10-09 17:42:30 · 8 answers · asked by Freebrum 3 in Science & Mathematics ➔ Mathematics
y = (3x^2 - 4)^(-5)
dy/dx = -5*(3x^2 - 4)^(-6) * d/dx (3x^2 - 4)
= -5*(3x^2 - 4)^(-6) * 6x
= -30x /(3x^2 - 4)^6
2007-10-09 17:45:39 · answer #1 · answered by Dr D 7 · 3⤊ 1⤋
x²
y = 1/(3x² - 4)^5 can be written as
y=(3x² - 4)^ -5
so follow the rules of derivatives. bring the exponent down in front
-5(3x² - 4)^-6 (3x² - 4)'
which is
-5(3x² - 4)^-6 (6x)
which is
-5(6x) / ((3x² - 4)^6)
which is
-30x / ((3x² - 4)^6)
I hope this is right.
2007-10-09 17:51:19 · answer #2 · answered by azianshrimp 2 · 0⤊ 1⤋
re-write as: (3x^2-4)^-5 Let u - 3x^2-4
y = u^-5
dy/dx = dy/du * du/dx
dy/du = -5u^-6
du/dx = 6x
dy/dx = 6x * -5(3x^2-4)^-6
= -30x / (3x^2-4)^6
2007-10-09 17:49:40 · answer #3 · answered by Alan 6 · 0⤊ 0⤋
quotient rule
(3x^2 - 4)^5(0) - (1)( 5(3x^2 - 4)^4)(6x) / ((3x^2 - 4)^5)^2
(-30x)(3x^2 - 4)^4 / (3x^2 - 4)^7
2007-10-09 17:47:34 · answer #4 · answered by xdirty_martinix 3 · 0⤊ 2⤋
43
2007-10-09 17:44:41 · answer #5 · answered by Anonymous · 1⤊ 2⤋
-5(3x^2-4)^-6 *(6x)= -30x/ (3x^2-4)^6
2007-10-09 17:45:59 · answer #6 · answered by ik3ra 2 · 1⤊ 1⤋
y = ( 3 x ² - 4 )^( - 5 )
dy/dx = ( - 5 )( 3 x ² - 4 )^(- 6) ( 6 x )
dy/dx = (- 30 x ) / ( 3 x ² - 4 )^6
2007-10-09 21:19:51 · answer #7 · answered by Como 7 · 1⤊ 0⤋
y=(3x^2 - 4)^ -5
y ' = - 5(3x^2 - 4)^-6 *(6x)
y ' = 6x / (-15x^2 + 20) ^ 6
2007-10-09 17:53:54 · answer #8 · answered by Rayan Ghazi Ahmed 4 · 0⤊ 2⤋