See if you can answer this problem.
When setting the price of admission tickets for the amusement park, Tabitha wants the price for a two–child, two–adult family to be $100. She also wants the adult tickets to cost $8.00 more than twice the cost of a child's ticket. How much should a child's ticket cost?
2007-10-09 14:21:41 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
14 x 2 + (2 x 14 +8) x 2 = 100.
$14
-or- 6x +16 =100
100 - 16 = 84
6x = 84
x = 14
2007-10-09 14:27:59 · answer #1 · answered by curtisports2 7 · 1⤊ 2⤋
Call a child's ticket c
So an adult ticket is 2c + 8
The equation is 2{(c) + (2c + 8)} = 100
Divide out the 2 to get c + 2c + 8 = 50
Simplify to get 3c = 42
Divide by 3 to get c = 14
So a child's ticket is $14
An adult ticket must be 2(14) + 8
Which equals $36 -- the cost of an adult ticket
So 2 child's tickets is $28
And 2 adult tickets is $72
Your conditions are met, since $28 + $72 = $100
2007-10-09 21:39:58 · answer #2 · answered by Don E Knows 6 · 0⤊ 0⤋
Let's set the price of an adult's ticket to A, and the price of a child's ticket to C. Then,
2A + 2C = 100 and
A - 8 = C. Plugging this equation into the first equation gives us
2A + 2(A-8) = 100
2A + 2A -16 =100
4A = 116
A = 29
Then...
29-8 = 21
So a child's ticket should be $21.00
2007-10-09 21:27:18 · answer #3 · answered by Anonymous · 1⤊ 1⤋
hey thats mean!
girl above me!
8 dollars more than twice childs....
you do 2*2=4 + 8 more than = 12.
2007-10-09 21:26:27 · answer #4 · answered by Davyy♫ 5 · 1⤊ 1⤋
4 dollars cuz thats half of 8 duhh..!
2007-10-09 21:24:35 · answer #5 · answered by superstar 2 · 0⤊ 4⤋