Physics Question- Inclined plane/projectile?

Question

A man carelessly leaves his car on neutral on a 29.5 degree inclined plane on the edge of a cliff. The car rolls of the plane/ falls of the cliff with a velocity of 20 m/s. The ocean below the cliff is 12.6 meters from the edge of the cliff/incline. The accleration og gravity is 9.8m/s2 and air resistance is negligible. How far from the base of the cliff is the car when it hits the ocean ( in meters)

Answer 1

First, the horizontal speed at take-off is
cos(29.5)*20, and the vertical speed is
-sin(29.5)*20

the car will fall per
y(t)=12.6-sin(29)*20*t-.5*9.81*t^2
impact occurs when y(t)=0, solve for t
t=0.887
so the horizontal displacement is
x(0.887)=Cos(29.5)*20*0.887

15.4 m

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