A 1.52 kg bottle of vintage wine is lying horizontally in the rack. The two surfaces on which the bottle rests are 90.0° apart, and the right surface makes an angle of 45° with respect to the ground. Each surface exerts a force on the bottle that is perpendicular to the surface. What is the magnitude of each of these forces?
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2007-10-09 13:03:01 · 1 answers · asked by Marianna E 1 in Science & Mathematics ➔ Physics
These 2 forces have a resultant that is vertical, and since the bottle is supported and in equilibrium, the resultant vector, F, of those 2 has a magnitude equal to the weight of the bottle.
F = 1.52*9.8 Newtons. Note that from symmetry, the 2 original forces have equal magnitide.
To find that resultant, break each of the original 2 into components. If you take the original vectors:Fl, the left one, and Fr, the right one and break them into vertical and horizontal components you will find that the 2 horizontal components point in opposite directions and cancel each other. The 2 vertical components both point up so they add. Give them the name Flv and Frv.
Flv = Fl*sin45 = Vl*.707
Frv = Fr*.707
The resultant F I talked about in the 1st paragraph equals the sum Flv+Frv.
So F = 1.52*9.8 Newtons = Fl*1.414
The magnitude of Fl and Fr are the same. Good enough hint?
2007-10-09 15:03:55 · answer #1 · answered by sojsail 7 · 0⤊ 0⤋