Force Constant of Each spring?

Question

Two identical massless springs are hung from a horizontal surface. A block of mass 1.5kg is suspended from the pair of springs. The accel of grav is 9.81 m/s^2.
When the block is in equilibrium, each spring is stretched an additional 0.54m.
The force constant for EACH spring is?

I tried working this out myself, but would like other feedback.

F = (k)(x)
The only force acting on the springs is the weight of the block.
And x is given, 0.54m, by the stretching of the strings.

(1.5kg)(9.81m/s^2) = (k)(0.54m)

thus k = 27.25 BUT here is where i became confused, as their are two springs, would the force constant be half?? (seeing how the question is "What's the force constant of EACH spring?")

so, k1 = 27.25/2 = 13.625

Feedback Please!

Answer 1

Well my result is the same but maybe the logic would be better my way.

I would say that each spring is supporting 1/2 of the weight (1.5kg)(9.81m/s^2). And then set the result equal to k*x.