how do u simplify 5 radical 8 and 1 over 3 radical 27?

Answer 1

1) 20 radical 2
2) 1 radical 9

Answer 2

first you need to find the squares within the radicals so that you can pull them out: (R = radical)

1) 5R(8) = 5R(2x2x2) = 5R(2x[2^2]) so 5 x 2 R(2) = 10R(2)

2) 1/3R(27) = 1/3R(3x3x3) = 1/3R(3x[3^2]) so 1/(3 x 3)R(3) = 1/(9R(3))

but technically simplifying a radical means not leaving a radical sign in the denominator, so you multiply it against itself over itself (which equals 1):
1/9R(3) x R(3)/R(3) = R(3)/[9 x (R(3))^2] or R(3)/[9 x 3] = R(3)/27

Answer 3

5(2) radical 2

for the other one

1/(9 radical 3)

Answer 4

5qrt(8) = 5sqrt(4*2) = 5 sqrt(4)*sqrt(2) = 10sqrt(2)

1/(3sqrt(27) = 1/(3sqrt(9)8sqrt(3) = 1/(9sqrt(3))
= sqrt(3)/(9*3) = sqrt(3)/27