i want the radius of the orbit or the distance form the equator, the period of one orbit ans its speed.
2007-10-09 11:21:08 · 3 answers · asked by shaggy 1 in Science & Mathematics ➔ Astronomy & Space
Here are the orbital elements from the Heavens-Above web site.
Epoch (UTC): 12:48:02 AM, Sunday, October 07, 2007
Eccentricity: 0.6954632
Inclination: 019.7192°
Perigee Height: 1,100 km
Apogee Height: 35,257 km
Right Ascension of Ascending Node: 323.3204°
Argument of Perigee: 248.1622°
Revolutions per Day: 02.25602714
Mean Anomaly at Epoch: 028.1121°
Orbit Number at Epoch: 12834
2007-10-09 12:06:05 · answer #1 · answered by campbelp2002 7 · 0⤊ 0⤋
Google for "cloudsat NORAD # 29107"
Orbit radius is 702km x 703km.
Period: 98.8 min.
Speed can be estimated by
2 * pi * 702.5 km / 98.8 min
You get 744 meters / sec = 2680 km per hour = 1666 MPH
2007-10-09 19:11:35 · answer #2 · answered by Anonymous · 0⤊ 0⤋
This will get you started:
http://science.nasa.gov/realtime/jtrack/eob.html
.
2007-10-09 18:45:55 · answer #3 · answered by tlbs101 7 · 0⤊ 0⤋