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My problem is as follows: A sled is dragged along a horizontal path at a constant speed of 1.5 m/s by a rope that is inclined at an angle of 30.0° with respect to the horizontal (the figure below). The total weight of the sled is 470 N. The tension in the rope is 270 N. How much work is done by the rope on the sled in a time interval of 10.0 s? What equation would i use to figure this out? I cant seem to find one that also calculates work with tension of the rope.

2007-10-09 10:53:42 · 2 answers · asked by sportzblock 1 in Science & Mathematics Physics

2 answers

Work is force times displacement.

First, calculate the displacement. Since it is all horizontal
d=1.5*10
or 15 meters

Only the horizontal component of the rope tension does work, so
270*cos(30)*15

j

2007-10-10 05:49:16 · answer #1 · answered by odu83 7 · 0 0

Work Tension

2016-12-12 11:06:27 · answer #2 · answered by ? 4 · 0 0

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