Collision question- magnitude and kinetic energy?

Question

Suppose a golf ball has a mass of .05kg is hurled with a speed of 10 m/s at a heavy bowling ball of mass 1.5kg initially at rest and bounces elastically from the bowling ball.

Which ball has the greater momentum after collision. Why?
Which has the greater kinetic energy and why?

Answer 1

Using conservation of energy and conservation of momentum I get
bowling
speed 0.6452
momentum 0.9678
ke 0.3122

golf
speed -9.3548
momentum -0.4677
ke 2.1878

Answer 2

The momentum between the two is the same.

p = mv [ momentum = mass times velocity]

In a purely elastic collision, all the momentum of the golf ball - bowling ball system remains constant, so any momentum of the golf ball (initial p = .05 x 10 = .5 kgms^-1) is transferred to the bowling ball (initial p = 0) and they "share" the momentum.

pfinal(bowling ball) = pfinal(golf ball)

.025 kgms-1 = 1.5 kg vfinal (bowling ball) = .017 ms-1
.025 kgms-1 = .05 kg vfinal (golf ball) = .5 ms-1
However, the golf ball will have greater kinetic energy as

K= 1/2 mv^2.
Because the golf ball is lighter, it will retain a greater velocity, and since in the kinetic energy equation, v counts as a squared value

K bb = 1/2 (1.5) (.017)^2 = 2*10^-4
K gb = 1/2 (.05) * (.5)^2 = 6.3*10-1

So the golf ball retains a much higher kinetic energy.