Calculate the molar mass of a gas at 370. torr and 45°C if 183 ng occupies 0.206 µL.
2007-10-09 07:40:32 · 3 answers · asked by jnester0289 1 in Science & Mathematics ➔ Chemistry
47.6 grams per mole
at a ratio of 183 nanograms to 0.206 microlitres, you can scale it up to 183 milligrams for 0.206 litres
PV=nRT n= PV/RT
n= (370T) (0.206 L) / (62.36) (318 Kelvin)
moles = 0.0038435 for the 183 milligrams
0.183 grams / 0.0038435 mole equals 47.6 grams/mole
2007-10-09 08:01:14 · answer #1 · answered by Steve O 7 · 1⤊ 0⤋
lol its not that bad but really TEDIOUS ill give you a simple equation and itll be ajoke to figure out but man is your teacher a ***** i mean why give it in TORR and NANOGRAMS and MICROLITERS thats not even testing how smart you are its just DAMN TEDIOUS i hate teachers like that...its a mark of a bad teacher MOLAR MASS= massx(constant for torr)xtemprature(in kelvin)/(pressure x volume)
2016-05-19 23:52:30 · answer #2 · answered by ? 3 · 0⤊ 0⤋
You use the perfect gas law, PV = nRT where n = moles = g/mol wt.
So mol. wt. = gRT/PV
Convert 183ng to g and plug it in. Convert 0.206*mu*L to L and use that for V. P= 370torr. T = 318K. R= 62.3 L-torr/mol-K.
2007-10-09 07:51:03 · answer #3 · answered by steve_geo1 7 · 0⤊ 1⤋