I could use some help with this problem... Please?

Question

A 12.4 g bullet is fired horizontally into a 98 g wooden block initially at rest on a horizontal surface. After impact, the block slides 7.5 m before coming to rest. If the coefficient of kinetic friction between block and surface is 0.650, what was the speed of the bullet immediately before impact?
The answer I have is 94.01, which is incorrect, though it's within 10% of the correct answer.
Any help would be appreciated!

Answer 1

Momentum will be conserved, so
12.4*v1=110.4*v2

also, the work done by friction
110.4*9.81*0.65*7.5=.5*110.4*v2^2
v2=9.78
so v1= 87 m/s

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