2007-10-09 06:07:02 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry
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Sodium, a low density, silvery, metal reacts vigorously with chlorine, a dense, greenish-yellow, poisonous gas, in a 1 to 1 mole ratio, to produce a colorless (appears white when as fine powder) water-soluble solid; sodium chloride.
2007-10-09 06:17:09 · answer #1 · answered by Flying Dragon 7 · 0⤊ 0⤋
Sodium+Chlorine====>Sodium-chloride
2007-10-09 07:37:22 · answer #2 · answered by Sharada B 3 · 0⤊ 0⤋
Sodium + Chlorine = sodium chloride
so simple frend
2007-10-13 06:07:58 · answer #3 · answered by Prathamesh 2 · 0⤊ 0⤋
3MgBr2(aq) + 2Na3PO4(aq) --> Mg3(PO4)2(s) + 6NaBr(aq) adding KCl would be adding K+ and Cl-. the K+ and Cl- would remain aqueous because Mg, reacting with Cl- will form MgCl2(aq) and the K+ will form K3PO4(aq). you will still get Mg3(PO4)2(s). KCl is readily soluble leaving K+ and Cl-. the Sn is not reactive enough to displace the K in KCl so you would get a solution of KCl(aq) and a piece of Sn sitting on the bottom of the beaker C3H8(g) + 5O2(g) --> 3CO2(g) + 4H2O(l), combustion always produces CO2 and H2O if complete 2Mg(s) + O2(g) --> 2MgO(s) this is extremely important to know how to do.
2016-04-07 23:22:37 · answer #4 · answered by Anonymous · 0⤊ 0⤋
Na+ + Cl- ----------> NaCl
2007-10-09 06:11:38 · answer #5 · answered by toocool 1 · 1⤊ 0⤋