2007-10-09 05:35:27 · 9 answers · asked by tankwillmsg 1 in Science & Mathematics ➔ Mathematics
use the law ln a - ln b = ln a/b
so ln(x+5) - ln(3) = ln(x - 3)
ln((x+5)/3) = ln(x-3)
(x+5)/3 = (x-3)
x+5 = 3x -9
2x = 14
x= 7
2007-10-09 05:41:47 · answer #1 · answered by norman 7 · 0⤊ 0⤋
oaky first divide by 1n
x+5-3=x-3
hMM okay this is going to turn out as nothing, because the variable x is killed...are you sure the question is correct? if the equation was
1n(x+5) - 1n(3)= -1n(x-3)
then it would make sense but otherwise...im not sure
2007-10-09 05:39:29 · answer #2 · answered by The Ambition 4 · 0⤊ 0⤋
a million. 5(3-2n)+5n=sixty 5 2. Distribute the 5 into the parenthesis: 15-10n+5n=sixty 5 3. Simplify (-10n+5n=-5n): 15-5n=sixty 5 4. Subtract the 15 to the different fringe of the equation: -5n=50 5. Divide the two factors via -5: n= -10 6. Plug back in to be taught your answer: 5[3-2(-10)]+5(-10)=sixty 5 and there is your answer! :)
2017-01-03 08:19:34 · answer #3 · answered by Anonymous · 0⤊ 0⤋
x>3
(x+5)/3 =x-3 x+5=3x-9 so x= 7
2007-10-09 05:39:56 · answer #4 · answered by santmann2002 7 · 0⤊ 0⤋
ln((x+5)/3) = ln(x-3)
(x+5)/3 = (x-3)
x+5 = 3x -9
2x = 14
x= 7
using the logarithm laws, in this case lnx - ln y = ln(x/y)
2007-10-09 05:59:46 · answer #5 · answered by dreamer 3 · 0⤊ 0⤋
The answer is 2.
2007-10-09 05:39:14 · answer #6 · answered by Anonymous · 0⤊ 0⤋
In true Matrix fashion...there is no equation ; )
2007-10-09 05:38:04 · answer #7 · answered by vinny_says_relax 7 · 0⤊ 0⤋
n(x+5)-n(3)=n(x-3)
(nx+5n)-(3n)=nx-3n
nx+2n=nx-3n
5n=0
n=0
web: www.mathepower.com
2007-10-09 05:50:43 · answer #8 · answered by Anonymous · 0⤊ 0⤋
nx+5n-3n=nx-3n
nx+2n=nx-3n
2007-10-09 05:42:04 · answer #9 · answered by bernel1403 5 · 0⤊ 0⤋