___1___
1+2^1/3
1 divided by
1 + cube root of 2
2007-10-09 04:29:24 · 6 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
multiply by the numerater and the denominater 1-2^1/3
and there is your answer
2007-10-09 05:04:32 · answer #1 · answered by Rock 2 · 0⤊ 0⤋
1/ (1+ 2^1/3)
= (1 - 2^1/3 + 4^1/3)/ ((1+2^1/3)(1 - 2^1/3 + 4^1/3))
= (1 - 2^1/3 + 4^1/3) / (1+2)
= (1 - 2^1/3 + 4^1/3)/ 3
2007-10-09 04:47:27 · answer #2 · answered by Ivan D 5 · 0⤊ 0⤋
1/(1 + 2^(1/3)
using the relation (a^3 + b^3 = (a+b)(a^2 - ab + b^2)
multiply the given expression with
(1 - 2^(1/3) + 2^(2/3))/ (1 - 2^(1/3) + 2^(2/3))
=>[(1 - 2^(1/3) + 2^(2/3)]/ (1+ 2)
=>(1/3)[(1 - 2^(1/3) + 2^(2/3)]
2007-10-09 04:56:15 · answer #3 · answered by mohanrao d 7 · 0⤊ 0⤋
[ 1 - 2^(1/3) ]
---------------------------------
[1 - 2^(1/3)] [1 + 2^(1/3) ]
[ 1 - 2^(1/3) ]
--------------------
1 - 2^(2/3)
2007-10-09 05:17:53 · answer #4 · answered by Como 7 · 1⤊ 0⤋
(1-2^(1/3)+2^(2/3))/3 you just have to multiply it by
(1-2^(1/3)+2^(2/3)/(1-2^(1/3)+2^(2/3))
2007-10-09 04:46:40 · answer #5 · answered by Hikari 1 · 0⤊ 0⤋
mult by
1-cube root of 3
2007-10-09 04:44:45 · answer #6 · answered by Anonymous · 0⤊ 2⤋