2007-10-09 04:23:13 · 8 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
because a real squarred is a positive number
so no real solution for the equation:
x^2=a when a is negative
2007-10-09 04:28:09 · answer #1 · answered by Anonymous · 2⤊ 0⤋
It's just a question of definitions and consistency.
The square root of 4 is 2, and 2 times itself is 4. That is consistent and simple.
But with the equation X^2 + 1 = 0 there is no answer with real numbers. It's a real simple problem, but when you want to solve it you have to satisfy the condition that X^2 = -1 , and this required somebody to think up imaginary numbers. It's not real, and when first suggested nobody was really ready to accept it.
It turns out that it has application for electricity and other cool stuff, but it took a while to catch on. You are not the first to struggle with this question.
2007-10-09 11:37:48 · answer #2 · answered by archaeadoc 5 · 0⤊ 0⤋
By definition a root is a number when multiplied by itself gives you the original number you were seeking the root for. ie the root of nine is 3. 3*3=9
Since when you multiply any number, positive or negative, you will always get a positive number, there is no way to get a negative number, a negative square root has no real root
2007-10-09 11:29:16 · answer #3 · answered by Michelle M 2 · 0⤊ 0⤋
Because any real number multiplied by itself will give a positive answer.
So it is impossible to take the square root of a number, and have the answer be real, based on what I just said.
2007-10-09 11:28:09 · answer #4 · answered by Anonymous · 0⤊ 0⤋
Because, according to the properties of the real field, for every real x we have x * x = x^2 >=0, with equality if, and only if, x = 0. We have the properties
positive * positive = positive
negative * negative = positive
0 * any real number = any real number * 0 = 0.
So, if x is real, x^2 is never negative. If follows that, if y is any negative real number, then there's no real x such that x^2 = y.
2007-10-09 11:48:32 · answer #5 · answered by Steiner 7 · 0⤊ 0⤋
negative * negative is positive
there can be no negative perfect square and hence negative numbers have no real root
2007-10-09 11:30:58 · answer #6 · answered by Krazny Oktybr 3 · 0⤊ 0⤋
Because any real number multiplied by itself will give a positive answer.
2007-10-09 12:12:33 · answer #7 · answered by tom 1 · 0⤊ 0⤋
because anything that it is multiplied by itself will never equal -
1^2 = 1
(-1)^2=1
2007-10-09 12:06:51 · answer #8 · answered by Rock 2 · 0⤊ 0⤋