Math question?

1 ⤊

(6y^2 - 3y)(y + 7)

2007-10-09 04:15:41 · 3 answers · asked by tbond_1969 1 in Science & Mathematics ➔ Mathematics

What is the question ?

May be you want to expand ?
(6y^2-3y)(y+7)=6y^3+42y^2-3y^2-21y
= 6y^3+39y^2-21y

2007-10-09 04:17:49 · answer #1 · answered by Anonymous · 1⤊ 0⤋

y(6y-3)(y+7)
y(6y^2+39y-21)
6y^3+39y^2-21y

y = 0, 1/2, -7

hopefully that covered everything

2007-10-09 11:21:01 · answer #2 · answered by Ilya S 3 · 0⤊ 0⤋

6y^3 + 39y^2 - 21y
3y (2y^2 + 13y - 7)

2007-10-09 12:12:34 · answer #3 · answered by edith p 3 · 0⤊ 0⤋