4x - 3y = 10
8x - 6y = 20
2007-10-08 22:46:41 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
Either method.
2007-10-08 22:47:07 · update #1
4x - 3y = 10 --- (1)
8x - 6y = 20 --- (2)
(1) X 2
8x - 6y = 20 --- (3
(2) = (3)
Solutions for x and y are indefinite. (meaning they both can be any real number, any at all, as anything will satisfy both equations)
2007-10-09 00:52:19 · answer #1 · answered by milky s 4 · 0⤊ 0⤋
re- arrange either equation in terms of a single variable either x or y. Then substitute into the other and solve for a single variable. Once found then use the varibale in either original equation to find the second variable as follows;
8x - 6y = 20
8x = 20 + 6y
x = (20/8) + (6/8)y
substituting into first equation;
4((20/8) + (6/8)y) - 3y = 10
10 + 3y - 3y = 10
therefore y = 0
4x - 3y = 10
4x = 10
x = 10/4 = 2.5
Please note in some cases there may be more than one set of solutions to the equations.
hope this helps
2007-10-09 05:58:11 · answer #2 · answered by skibz26 4 · 0⤊ 0⤋
These equations are identical.
All that can be said is that:-
3y = 4x - 10
y = (4/3)x - 10/3
2007-10-09 06:05:52 · answer #3 · answered by Como 7 · 0⤊ 0⤋
The two equations describe the same line. The second equation is just the first equation with every term multiplied by two.
2007-10-09 05:52:30 · answer #4 · answered by Northstar 7 · 0⤊ 0⤋
plz check
the 1st and the 2nd equation are same
multiply first euation by 2 and u get 2nd equation
data is insufficient
2007-10-09 05:52:42 · answer #5 · answered by Gunjit M 2 · 0⤊ 0⤋