help me solve the following integrals?

Question

(A) (x+6x-5)dx

(B) (1/x+1/x)dx

(C) 6sqrt(x)dx

Answer 1

Question A
∫ x + 6 x - 5 dx = ∫ 7 x - 5 dx = 7 x ²/ 2 - 5 x + C
In case question is:-
∫ x² + 6 x - 5 dx = x ³ / 3 + 3 x ² - 5 x + C
Question B
If question is:-
∫ x / (x + 1) dx
∫ 1 - 1 / (x + 1) dx
x - log (x + 1) + C
If question is:-
∫ 2 / x dx
2 log x + C
Question C
∫ 6 x^(1/2) dx
6 x^(3/2) / (3/2) + C
4 x^(3/2) + C

Answer 2

(A) (x+6x-5)dx
simplify
7x-5 dx
7x^2/2 -5x+C

(B) (1/x+1/x)dx
simplify
2/x dx
2Inx+C
(C) 6sqrt(x)dx
6x^3/2 * (2/3) +C
4x^3/2 +C

Answer 3

1.∫(x+6x-5)dx=∫(7x-5)dx=7x^2/2-5x
2.∫(1/x+1/x)dx=∫(2/x)dx=2logx
3.∫6sqrt(x)dx=2*6xsqrt(x)/3=4xsqrt(x)