A rectangular piece of 4m x 5m is being rolled to fit and form the cylindrical surface of a metal container.Assuming thickness and base of the cylynder are accounted for.What is the volume of this container(take II to be 3.14)
2007-10-08 20:41:56 · 4 answers · asked by Huyoon m 1 in Science & Mathematics ➔ Mathematics
Volume of a cylinder is approx. equal to 3.14 * radius squared * height.
If you roll the piece lengthwise, the height will be 4, and the circumference of the base will be 5...5 divided by 3.14 is about 1.592, the diamter. The radius is 1.592 divided by 2, which is about 0.796.
So, the volume is approximately 3.14 * 0.796^2 * 4, which is about 7.96 cubic meters.
If you roll the piece width-wise, you'll get a different result. The height would be 5, and the circumference of the base would be 4. 4 divided by 3.14 is 1.274, the diameter. So .637 would be the radius. The volume would then be 3.14 * 0.637^2 * 5 =
6.37 cubic meters.
2007-10-08 20:52:41 · answer #1 · answered by SoulDawg 4 UGA 6 · 0⤊ 0⤋
There seems to be some disagreement among the answerers here, so I'll add my vote.
Volume v = pi*r^2*h where r is radius, h is height.
Circumference c = 2*pi*r so r = c/(2*pi).
So, substituting, v = pi*c^2*h/(4*pi)
If we take c=5, h=4 then v = 25/pi, or about 7.96
If we take h=5, c=4 then v = 20/pi, or about 6.37.
2007-10-08 21:12:47 · answer #2 · answered by Sangmo 5 · 0⤊ 0⤋
If the 4" side is wrapped, the equation would be 5 x 4pi meters.
If the 5" side is wrapped, the equation would be 4 x 5pi meters.
BOTH are EQUIVALENT! 20 pi meters is the volume.
Think of a circle growing the length if the cylindar.
(short side) x (longer side)(pi) = (short)(long)(3.1415)
2007-10-08 21:02:24 · answer #3 · answered by lacompsr 1 · 1⤊ 1⤋
20m volume is 20+3.14=24.12volume//
2007-10-08 20:45:41 · answer #4 · answered by Anonymous · 0⤊ 1⤋