Find the derivative of F when
F(x)= f (x+1/x+7)
and f is defferntiable.
Answers.
f ' (6/x+7)^2)
f (6/(x+7)^2)
6/(x+7)^2 f (x+1/x+7)
-6/(x+7)^2 f ' (x+1/x+7)
6/(x+7)^2 f ' (x+1/x+7)
-6/(x+7)^2 f (x+1/x+7)
2007-10-08 17:28:17 · 3 answers · asked by michelle 1 in Science & Mathematics ➔ Mathematics
Based on the answer choices, the problem should've been stated F(x) = f((x+1)/(x+7)).
So let u = (x+1)/(x+7)
by quotient rule u '(x) = 6/(x+7)^2
so F '(x) = u '(x) * f '(u) = 6/(x+7)^2 * f '((x+1)/(x+7))
2007-10-08 17:42:14 · answer #1 · answered by Larry B 2 · 0⤊ 0⤋
6/(x+7)^2 f ' (x+1/x+7).. it's a chain rule question... hope it helped... gl
2007-10-09 00:35:52 · answer #2 · answered by orange 2 · 0⤊ 0⤋
Use the chain rule. Let
u = x+1/x+7 then F(x) = f(u)
and now
dF(x)/dx = du/dx df(u)/du = (1-1/x^2)*df(u)/du
2007-10-09 00:34:54 · answer #3 · answered by nyphdinmd 7 · 0⤊ 0⤋