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the compound X2O3 Is reduced by hydrogen according to the reaction: X2O3 + 3H2---------> 2X+3H20.

IF 9.30 g of X2O3 produce 3.64 g of h20, what is the element x?

2007-10-08 16:12:29 · 3 answers · asked by ccutestuff2001 2 in Science & Mathematics Chemistry

3 answers

Welcome back, Cary R. We work backwards on this one, but the main point to remember is that the equation is used to determine moles in the problem and then you convert to mass.
So we have produced 3.64 g of H20. Divide by the mol wt of water, we have about 0.2 moles.
The reaction tells us that 1 mole of X2O3 is needed for 3 moles of water, so by proportion,
moles of X2O3= 0.066 appx. Now, is 0.066 moles is 9.3 grams, you can find the mol wt of X2O3 by proportion: 9.3/0.066=X/1= 150 appx.
of the 150 grams/mole, 48 is from oxygen, so X2=150-48=102 and X=51. Now you have to find an element with a valance of +3 and an atomic wt of about 51.

2007-10-08 16:24:00 · answer #1 · answered by cattbarf 7 · 0 0

there is no element x
theres xe which is xenon

2007-10-08 16:15:13 · answer #2 · answered by Anonymous · 0 1

carbon

2007-10-08 16:16:22 · answer #3 · answered by Anonymous · 0 1

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