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2007-10-08 16:01:08 · 20 answers · asked by Anonymous in Science & Mathematics Mathematics

20 answers

an equation?

A line?

A series of numbers and letters?

edit: the guy above me clearly doesn't realize that x and y are different, and many of the answers on here say that x and y are both equal to 1. This is WRONG!!!! This is only ONE solution to this equation, there are infinitely many.

divide out a common factor of three from the equation to get:

4 = 3x + y

rearrange to standard form

y = -3x + 4.

y and x are clearly not ONLY 1.

2007-10-08 16:03:25 · answer #1 · answered by mazdamandan 4 · 1 0

12= 9x + 3y
12= 9(1) + 3(1)
12=12

x= 1

2007-10-08 16:10:49 · answer #2 · answered by Anonymous · 0 0

x=1

2007-10-08 16:04:16 · answer #3 · answered by gabound75 5 · 0 4

its an equation of a line.

do you need to solve for x or y?

for x,

12 = 9x +3y
9x = 12 -3y
x = (12-3y) / 9
x = 4/3 - 1/3y
x = (4-y)/ 3

for y,
12=9x+3y
12-9x=3y
y = (12-9x)/3
y = 4 - 3x

You need to have another equation to determine the value of x and y.

2007-10-08 16:11:58 · answer #4 · answered by aka_gian 3 · 0 0

equation of a straight line
12=9x+3y
3y=-9x+12
y=-3x+4
x=0, y=4
y=0, x=4/3

2007-10-08 16:07:25 · answer #5 · answered by slick_licker88 3 · 0 0

well 9 + 3 = 12

so both x and y = 1

2007-10-08 16:04:10 · answer #6 · answered by Nana Callie loves to sing 4 · 0 4

9*1 = 9
3*1 = 3
9+3=12
12=9(1)+3(1)
x and y are both 1

2007-10-08 16:14:42 · answer #7 · answered by Anonymous · 0 0

3y + 9x =12
y + 3x = 4
y = 4 - 3x ---------equation NO.1
3x = 4 - y ---------equation NO.2
put eq.1 into eq.2 we get
3x = 4 - (4 - 3x)
3x = 4 - 4 + 3x
3x = 3x
therefor
x=1
Now put this value into eq.2 we get
3 = 4 - y
3 - 4 = - y
-1 = -y
therefor
y = 1

2007-10-09 00:24:19 · answer #8 · answered by Rayan Ghazi Ahmed 4 · 0 0

An equation.

Linear equation in standard form.

2007-10-08 16:03:35 · answer #9 · answered by UnknownD 6 · 0 0

All are divisible by 3 so...

try to listen at school so that you won't have to ask others.

4=3x+y

2007-10-08 16:05:12 · answer #10 · answered by jace 4 · 0 0

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