Chemistry.....Help!!!?
I can't figure this dang thing out:
Assume the reaction of 51.47 g of Ge in the following reaction to determine the other quantities.
3Ge + 2N2 -> 1Ge3N4
moles of Ge reacting =
moles of N2 required =
moles of Ge3N4 formed =
mass of Ge3N4 formed =
I have ge and n2 as .71 and .47, which are correct, but I can't seem to figure out that last two. Please help!!!
2007-10-08 15:57:52 · 2 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry
51.47 g Ge * 1 mole/ (mass of Ge) * 1mol Ge3N4 / 3mol Ge
and then for the mass contine the expression with
molar mass of Ge3N4 / 1 mol Ge3N4
2007-10-08 16:03:51 · answer #1 · answered by Marcus C 3 · 0⤊ 0⤋
Why not? You did the first two, just follow the reaction along. The reaction indicates three moles of Ge is needed to produce one mole of the nitride. So, moles= .243. Now multiply that by the mole wt of Ge3N4 to get your mass.
2007-10-08 23:03:17 · answer #2 · answered by cattbarf 7 · 0⤊ 0⤋