What volume of water would have to be added to 65.4g glucose(C6H12O6) to make a 0.3 M solution?

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What volume of water would have to be added to 65.4g glucose(C6H12O6) to make a 0.3 M solution?

2007-10-08 15:01:10 · 1 answers · asked by shauna s 1 in Science & Mathematics ➔ Chemistry

1 answers

Molecular weight of C6H12O6

= 6*(12) + 12*(1) + 6*(16)

= 180 g/mol

(65.4 g)/(180 g/mol) ~ 0.3633 mols glucose

Volume of water needed = mols of glucose/molarity of soln.

= 0.3633 mols/(0.3 mols/L)

~ 1.21 L

2007-10-08 15:21:07 · answer #1 · answered by The K-Factor 3 · 0⤊ 0⤋