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A sheet of gold weighing 10.0g and at a temperature of 18.0 degrees celcius is placed flat on a sheet of iron weighing 20.0g and at a temperature of 55.6 degrees celcius. What is the final temperature of the combined metals? Assume that no heat is lost to the surroundings.

Could you show step by step on how to do it. Please and thank you.

2007-10-08 14:38:23 · 1 answers · asked by bryon_barker 2 in Science & Mathematics Chemistry

1 answers

We also need heat capacity data:
Gold: (25°C) 25.418 J/(mol·K), or 0.12905 J/(g·K)
Iron: (25°C) 25.10 J/(mol·K), or 0.44946 J/(g·K)
Suppose the final temperature of the combined metals is T.
10.0*0.12905*(T-18.0) = 20.0*0.44946*(55.6 - T)
T = 50.9 (degree C)

2007-10-08 16:03:32 · answer #1 · answered by Hahaha 7 · 0 0

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