Chemistry.....Help!!!?

Question

I can't figure this dang thing out:

Assume the reaction of 51.47 g of Ge in the following reaction to determine the other quantities.

3Ge + 2N2 -> 1Ge3N4
moles of Ge reacting =
moles of N2 required =
moles of Ge3N4 formed =
mass of Ge3N4 formed =

I have ge and n2 as .71 and .47, which are correct, but I can't seem to figure out that last two. Please help!!!

Answer 1

Let us take your correct results. So:
3Ge + 2N2 -> 1Ge3N4
moles of Ge reacting = .71
moles of N2 required = .47 (=0.71*2/3)
Now assume that the reaction is 100% complete, so 3 Mol of Ge would generate 1 Mol of Ge3N4:
moles of Ge3N4 formed = 0.71/3 = 0.24
mass of Ge3N4 formed = 0.24*(formula mass of Ge3N4)