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A mixture of gases contains 0.34 mole CH4, 0.44 mole C2H6, and 0.28 mole C3H8. The total pressure is 1.50 atm. Calculate the partial pressures of the gases.
PCH4

PC2H6

PC3H8

2007-10-08 13:46:10 · 1 answers · asked by ws 3 in Science & Mathematics Chemistry

1 answers

0.34 + 0.44 + 0.28 = 1.16
The partial pressures of CH4: (0.34/1.16)*1.5 atm
The partial pressures of C2H6: (0.44/1.16)*1.5 atm
The partial pressures of C3H8: (0.28/1.16)*1.5 atm

2007-10-08 17:33:11 · answer #1 · answered by Hahaha 7 · 0 0

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