Help with simple algebra?

Question

The problem is: Solve for X:

(x+1)^2 (x-3)^2 (x+3)^2 - (x+1)^3 (x-3)^2 (x+3)^2 = 0


Would the (x-3)^2s and the (x+3)^2s just cancel leaving (x-1)^2 - (x+1)^3??

Where do I go from there??

Answer 1

Cancel the (x+1)'s to get:
(x-3)^2(x+3)^2 = (x+1)(x-3)^2(x+3)^2
Now cancel out the (x-3)'s:
(x+3)^2 = (x+1)(x+3)^2
Now cancel the (x+3)'s to get
x+1 = 1
x= 1-1 = 0

Answer 2

x=0

Answer 3

(x+1)²(x-3)²(x+3)² - (x+1)³(x-3)²(x+3)² = 0
(x+1)²(x-3)²(x+3)² [1 - (x+1)] = 0
(x+1)²(x-3)²(x+3)² [-x] = 0
setting each factor to 0,
x = -1 or
x = ±3 or
x = 0