express the quadratic equation in standard form: Given: f(x) = 2x^2- 6x -1?

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express the quadratic equation in standard form: Given: f(x) = 2x^2- 6x -1?

2007-10-08 12:41:39 · 3 answers · asked by uknowuluvme 1 in Science & Mathematics ➔ Mathematics

3 answers

1. f(x) = 2x^2- 6x -1
2. y + 1 = 2 (x^2 - 3x + __)
3. Complete the square
-3/2^2 = 9/4
y + 1 + 9/4 = 2 (x^2 - 3x + 9/4)
y + 13/4 = 2 (x - 3/2)^2
4. Answer: f(x) = 2 (x - 3/2)^2 - 13/4

2007-10-08 13:00:50 · answer #1 · answered by lee 1 · 0⤊ 0⤋

2x^2- 6x -1=0

2007-10-08 12:46:47 · answer #2 · answered by ironduke8159 7 · 0⤊ 0⤋

ax^2+bx+c=0

here in your case:

ax^2-bx-c=0

hope that helps ....

2007-10-08 12:58:08 · answer #3 · answered by Aeromina 2 · 0⤊ 0⤋