HELP PLEASE !!! BRAIN FREEZE...
2007-10-08 12:15:32 · 10 answers · asked by CelticMoonGoddess 2 in Science & Mathematics ➔ Mathematics
(x+1)²=4
(x+1)(x+1)=4
x²+2x+1=4
x²+2x-3=0
(x-1)(x+3)=0
x-1=0 and x+3=0
x=1 and x=-3
hope this helps. =]
2007-10-08 12:24:03 · answer #1 · answered by asdfjkl; 2 · 0⤊ 0⤋
(x + 1)^2 = 4 --> x+1=±â4 --> x+1=±2
--> x= -1±2 --> x=1 or x=-3
saludos.
2007-10-08 12:36:25 · answer #2 · answered by lou h 7 · 0⤊ 0⤋
x ² + 2 x + 1 = 4
x ² + 2 x - 3 = 0
( x + 3 ) ( x - 1 ) = 0
x = - 3 , x = 1
2007-10-10 08:12:21 · answer #3 · answered by Como 7 · 0⤊ 0⤋
(x + 1)^2 = 4, so
(x + 1)(x + 1) = 4, so
x^2 + 2x + 1 = 4, so
x^2 + 2x - 3 = 0, so
(x + 3)(x -1) = 0, so
x + 3 = 0, OR x - 1 = 0, so
x = -3, OR x = 1.
Hope this helps, Twiggy.
2007-10-08 12:26:05 · answer #4 · answered by Twiggy 7 · 0⤊ 0⤋
(x+1)^2 - 2^2 = 0
(x+1+2) *(x+1-2) = 0
(x+3) *(x-1) = 0
x = - 3 or x = 1
2007-10-08 12:22:07 · answer #5 · answered by the_science_guy 1 · 0⤊ 0⤋
[x+1]^2=4;
taking sqrt on both sides we get:
[x+1]=2, or [x+1]=-2;
this gives ;
x=1 or x=-3
2007-10-08 14:26:36 · answer #6 · answered by karan s 3 · 0⤊ 0⤋
(x + 1)^2 = 4
(x + 1) = sqr rt (4)
(x + 1) = +2, -2
x = +1, -3
2007-10-08 12:25:12 · answer #7 · answered by skeptik 7 · 0⤊ 0⤋
Take square root of both sides, (x+1)=2
x=1.
2007-10-08 12:22:46 · answer #8 · answered by Jim J 5 · 0⤊ 0⤋
(x+1)^2=4
sqrt. (x+1)^2= sqrt. 4
x+1=2
x=1
2007-10-08 12:21:14 · answer #9 · answered by s-t-e-v-e-n 4 · 0⤊ 1⤋
answer is x=1,-3
trust me i cheated on this lol
2007-10-08 12:22:05 · answer #10 · answered by Anonymous · 0⤊ 1⤋