What is the derivative of y=sin(x^3+4)ln(x^2+5)?

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2007-10-08 11:15:35 · 3 answers · asked by Clay H 1 in Science & Mathematics ➔ Mathematics

y' = cos(x^3+4)(3x^2)ln(x^2+5) + sin(x^3+4)[2x/(x^2+5)]

2007-10-08 11:21:32 · answer #1 · answered by sahsjing 7 · 0⤊ 0⤋

2x sin(x^3+4)/x^2+5 + (3x^2)ln(x^2+5)cos(x^3+4)

2007-10-08 11:22:35 · answer #2 · answered by xandyone 5 · 0⤊ 0⤋

y' = 3x^2cos(x^3+4)ln(x^2+5) +2xsin(x^3+4)/ln(x^2+5)

2007-10-08 11:22:23 · answer #3 · answered by ironduke8159 7 · 0⤊ 0⤋